Answer
$\frac{x}{8}$
Work Step by Step
$\frac{2x^{2}-5x}{16x-40}=\frac{x(2x-5)}{8(2x-5)}=\frac{x}{8}\times\frac{(2x-5)}{(2x-5)}=\frac{x}{8}\times1=\frac{x}{8}$
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