Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - 6.1 Exercises: 31

Answer

$\frac{(x+3)}{2x(x-3)}$

Work Step by Step

$\frac{4x(x+3)}{8x^{2}(x-3)}=\frac{4x}{8x^{2}}\times\frac{(x+3)}{(x-3)}=\frac{1}{2x}\times\frac{(x+3)}{(x-3)}=\frac{(x+3)}{2x(x-3)}$
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