Answer
not factorable
Work Step by Step
$\bf{\text{Solution Outline:}}$
The given expression, $
k^2-6k+16
,$ is prime.
$\bf{\text{Solution Details:}}$
In the trinomial expression above, $b=
-6
,\text{ and } c=
16
.$ Using the factoring of trinomials in the form $x^2+bx+c,$ there are no two numbers whose product is $c$ and whose sum is $b.$ Hence, the given expression is $\text{
not factorable
.}$