## Intermediate Algebra (12th Edition)

$(10+y)(100-10y+y^2)$
$\bf{\text{Solution Outline:}}$ To factor the given expression, $1000+y^3 ,$ use the factoring of the sum/difference of $2$ cubes. $\bf{\text{Solution Details:}}$ Using $(a\pm b)(a^2\mp ab+b^2)$ or the factoring of the sum/difference of $2$ cubes, the expression above is equivalent to \begin{array}{l}\require{cancel} (10+y)[(10)^2-10(y)+(y)^2] \\\\= (10+y)(100-10y+y^2) .\end{array}