Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 5 - Section 5.3 - Special Factoring - 5.3 Exercises: 16

Answer

$(h+k+3)(h+k-3)$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To factor the given expression, $ (h+k)^2-9 ,$ use the factoring of the difference of $2$ squares. $\bf{\text{Solution Details:}}$ Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of $2$ squares, the factored form of the expression above is \begin{array}{l}\require{cancel} [(h+k)+3][(h+k)-3] \\\\= (h+k+3)(h+k-3) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.