Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 5 - Section 5.1 - Greatest Common Factors and Factoring by Grouping - 5.1 Exercises: 15

Answer

$8k(k^{2}+3)$

Work Step by Step

The greatest common factor of $8k^{3}+24k$ is $8k$. We can use the distributive property to factor out the greatest common factor. 1. $8k^{3}+24k$ 2. $8k\times k^{2}+8k\times3$ 3. $8k(k^{2}+3)$
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