## Intermediate Algebra (12th Edition)

$3y+4-\dfrac{5}{y}$
Dividing the denominator to each of the terms of the numerator, the given expression, $\dfrac{9y^2+12y-15}{3y} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{9y^2}{3y}+\dfrac{12y}{3y}-\dfrac{15}{3y} \\\\= 3y+4-\dfrac{5}{y} .\end{array}