Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.5 - Dividing Polynomials - 4.5 Exercises: 14

Answer

$\dfrac{2b}{a}+\dfrac{5}{3}+\dfrac{3c}{a}$

Work Step by Step

Dividing the denominator to each of the terms of the numerator, the given expression, $ \dfrac{12ab^2c+10a^2bc+18abc^2}{6a^2bc} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{12ab^2c}{6a^2bc}+\dfrac{10a^2bc}{6a^2bc}+\dfrac{18abc^2}{6a^2bc} \\\\= \dfrac{2b}{a}+\dfrac{5}{3}+\dfrac{3c}{a} .\end{array}
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