## Intermediate Algebra (12th Edition)

$\dfrac{2b}{a}+\dfrac{5}{3}+\dfrac{3c}{a}$
Dividing the denominator to each of the terms of the numerator, the given expression, $\dfrac{12ab^2c+10a^2bc+18abc^2}{6a^2bc} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{12ab^2c}{6a^2bc}+\dfrac{10a^2bc}{6a^2bc}+\dfrac{18abc^2}{6a^2bc} \\\\= \dfrac{2b}{a}+\dfrac{5}{3}+\dfrac{3c}{a} .\end{array}