Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.5 - Dividing Polynomials - 4.5 Exercises - Page 311: 10

Answer

$8-\dfrac{9}{x}+\dfrac{3}{2x^2}$

Work Step by Step

Dividing the denominator to each of the terms of the numerator, the given expression, $ \dfrac{64x^3-72x^2+12x}{8x^3} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{64x^3}{8x^3}-\dfrac{72x^2}{8x^3}+\dfrac{12x}{8x^3} \\\\= 8-\dfrac{9}{x}+\dfrac{3}{2x^2} .\end{array}
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