Answer
32
Work Step by Step
We are given that $f(x)=x^{2}-9$, $g(x)=2x$, and $h(x)=x-3$.
We know that $(fh)(x)=f(x)\times h(x)$.
Therefore, $(fh)(-1)=((-1)^{2}-9)\times(-1-3)=(1-9)\times(-4)=-8\times-4=32$.
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