Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 111

Answer

$2x^{3}-18x$

Work Step by Step

We are given that $f(x)=x^{2}-9$, $g(x)=2x$, and $h(x)=x-3$. We know that $(fg)(x)=f(x)\times g(x)$. Therefore, $(fg)(x)=(x^{2}-9)\times(2x)=x^{2}\times2x-9\times2x=2x^{2+1}-18x=2x^{3}-18x$.
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