Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 106

Answer

$18x^{2}-24x$

Work Step by Step

We are given that $f(x)=3x$ and $g(x)=6x-8$. We know that $(fg)(x)=f(x)\times g(x)$. Therefore, $(fg)(x)=(3x)\times(6x-8)=3x\times6x+3x\times-8=18x^{1+1}+(-24x)=18x^{2}-24x=18x^{2}-24x$.
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