Answer
$10x^{2}-2x$
Work Step by Step
We are given that $f(x)=2x$ and $g(x)=5x-1$.
We know that $(fg)(x)=f(x)\times g(x)$.
Therefore, $(fg)(x)=(2x)\times(5x-1)=2x\times5x+2x\times-1=10x^{1+1}+(-2x)=10x^{2}-2x=10x^{2}-2x$.
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