Answer
8
Work Step by Step
We are given that $f(x)=x^{2}+4$, $g(x)=2x+3$, and $h(x)=x-5$.
We are asked to find $(f∘g)(-\frac{1}{2})$. We know that $(f∘g)(x)=f(g(x))$.
Therefore, $(f∘g)(-\frac{1}{2})=f(g(-\frac{1}{2}))=f(2(-\frac{1}{2})+3)=f(-1+3)=f(2)=2^{2}+4=4+4=8$.