Answer
-2
Work Step by Step
We are given that $f(x)=x^{2}-9$, $g(x)=2x$, and $h(x)=x-3$.
We are asked to find the value of $(g+h)(\frac{1}{3})$. We know that $(g+h)(x)=g(x)+h(x)$.
Therefore, $(g+h)(\frac{1}{3})=(2(\frac{1}{3}))+(\frac{1}{3}-
\frac{9}{3})=(\frac{2}{3})+(\frac{1-9}{3})=(\frac{2}{3})+(\frac{-8}{3})=\frac{2}{3}-\frac{8}{3}=\frac{2-8}{3}=\frac{-6}{3}=-\frac{6}{3}=-2$.