Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.3 - Polynomial Functions, Graphs, and Composition - 4.3 Exercises: 38

Answer

-2

Work Step by Step

We are given that $f(x)=x^{2}-9$, $g(x)=2x$, and $h(x)=x-3$. We are asked to find the value of $(g+h)(\frac{1}{3})$. We know that $(g+h)(x)=g(x)+h(x)$. Therefore, $(g+h)(\frac{1}{3})=(2(\frac{1}{3}))+(\frac{1}{3}- \frac{9}{3})=(\frac{2}{3})+(\frac{1-9}{3})=(\frac{2}{3})+(\frac{-8}{3})=\frac{2}{3}-\frac{8}{3}=\frac{2-8}{3}=\frac{-6}{3}=-\frac{6}{3}=-2$.
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