Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.3 - Polynomial Functions, Graphs, and Composition - 4.3 Exercises - Page 295: 37

Answer

$-\frac{9}{4}$

Work Step by Step

We are given that $f(x)=x^{2}-9$, $g(x)=2x$, and $h(x)=x-3$. We are asked to find the value of $(g+h)(\frac{1}{4})$. We know that $(g+h)(x)=g(x)+h(x)$. Therefore, $(g+h)(\frac{1}{4})=(2(\frac{1}{4}))+(\frac{1}{4}- \frac{12}{4})=(\frac{2}{4})+(\frac{1-12}{4})=(\frac{2}{4})+(\frac{-11}{4})=\frac{2}{4}-\frac{11}{4}=\frac{2-11}{4}=\frac{-9}{4}=-\frac{9}{4}$.
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