Answer
0
Work Step by Step
We are given that $f(x)=x^{2}-9$, $g(x)=2x$, and $h(x)=x-3$.
We are asked to find the value of $(g+h)(1)$. We know that $(g+h)(x)=g(x)+h(x)$.
Therefore, $(g+h)(1)=(2(1))+(1-3)=(2)+(-2)=2-2=0$.
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