## Intermediate Algebra (12th Edition)

We are given the function $f(x)=2x^{2}-4x+1$. In order to find the specified values, we can plug the values into the function and solve. a. $f(-1)= 2(-1)^{2}-4(-1)+1=2\times(-1\times-1)-4\times-1+1=(2\times1)-(-4)+1=(2)+4+1=2+4+1=7$ b. $f(2)= 2(2)^{2}-4(2)+1=2\times(2\times2)-4\times2+1=(2\times4)-(8)+1=(8)-8+1=8-8+1=1$ c. $f(0)= 2(0)^{2}-4(0)+1=2\times(0\times0)-4\times0+1=(2\times0)-(0)+1=(0)-0+1=0-0+1=1$