Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.2 - Adding and Subtracting Polynomials - 4.2 Exercises - Page 286: 87

Answer

$12x^2+8x+5$

Work Step by Step

Adding all the side measurements, then the perimeter of the given triangle is \begin{array}{l}\require{cancel} (4x^2+2)+(6x^2+5x+2)+(2x^2+3x+1) \\\\= 4x^2+2+6x^2+5x+2+2x^2+3x+1 \\\\= (4x^2+6x^2+2x^2)+(5x+3x)+(2+2+1) \\\\= 12x^2+8x+5 .\end{array}
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