Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.2 - Adding and Subtracting Polynomials - 4.2 Exercises - Page 286: 81

Answer

$-4m^2+4n^2-7n$

Work Step by Step

Removing the grouping symbols and then combining like terms, the given expression, $ (-4m^2+3n^2-5n)-[(3m^2-5n^2+2n)+(-3m^2)+4n^2] ,$ simplifies to \begin{array}{l}\require{cancel} -4m^2+3n^2-5n-[3m^2-5n^2+2n-3m^2+4n^2] \\\\= -4m^2+3n^2-5n-3m^2+5n^2-2n+3m^2-4n^2 \\\\= (-4m^2-3m^2+3m^2)+(3n^2+5n^2-4n^2)+(-5n-2n) \\\\= -4m^2+4n^2-7n .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.