Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.2 - Adding and Subtracting Polynomials - 4.2 Exercises - Page 286: 79

Answer

$3y^2-4y+2$

Work Step by Step

In symbols, the given statement is equivalent to \begin{array}{l}\require{cancel} 7y^2-6y+5-(4y^2-2y+3) .\end{array} Removing the grouping symbols and then combining like terms, the expression abvoe simplifies to \begin{array}{l}\require{cancel} 7y^2-6y+5-4y^2+2y-3 \\\\= (7y^2-4y^2)+(-6y+2y)+(5-3) \\\\= 3y^2-4y+2 .\end{array}
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