Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises - Page 276: 4

Answer

$y^{2+6}=y^{8}$

Work Step by Step

We are given that $y^{2}\times y^{6}=y^{12}$. However, according to the table at the bottom of page 271, we know that $a^{m}\times a^{n}=a^{m+n}$. Therefore, $y^{2}\times y^{6}=y^{2+6}=y^{8}$.
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