## Intermediate Algebra (12th Edition)

$y^{2+6}=y^{8}$
We are given that $y^{2}\times y^{6}=y^{12}$. However, according to the table at the bottom of page 271, we know that $a^{m}\times a^{n}=a^{m+n}$. Therefore, $y^{2}\times y^{6}=y^{2+6}=y^{8}$.