Answer
-2
Work Step by Step
According to page 267, $a^{0}=1$ (where $a$ is a nonzero real number). In other words, we know that any nonzero real number raised to a power of 0 will equal 1.
Therefore, $-8^{0}-k^{0}=-(8^{0})-(k^{0})=-(1)-(1)=-1-1=-2$.
Recall that the bases of the exponents are 8 and k, respectively, and not -8 and –k.