Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 34

Answer

-2

Work Step by Step

According to page 267, $a^{0}=1$ (where $a$ is a nonzero real number). In other words, we know that any nonzero real number raised to a power of 0 will equal 1. Therefore, $-8^{0}-k^{0}=-(8^{0})-(k^{0})=-(1)-(1)=-1-1=-2$. Recall that the bases of the exponents are 8 and k, respectively, and not -8 and –k.
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