## Intermediate Algebra (12th Edition)

$\frac{4^{3}}{a^{3}}$
3. We are given that $(\frac{4}{a})^{3}=\frac{4^{3}}{a}$ (where $a\ne0$). However, according to the table on page 270, we know that $(\frac{a}{b})^{m}=\frac{a^{m}}{b^{m}}$ (where $b\ne0$). Therefore, $(\frac{4}{a})^{3}=\frac{4^{3}}{a^{3}}$ (where $a\ne0$).