Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 22

Answer

a. D. 8 b. E. -8 c. B. 1 d. B. 1

Work Step by Step

According to page 267, $a^{0}=1$ (where $a$ is a nonzero real number). In other words, we know that any nonzero real number raised to a power of 0 will equal 1. Therefore, a. $8x^{0}=8\times1=8$ b. $-8x^{0}=-8\times1=-8$ c. $(8x)^{0}=8^{0}x^{0}=1\times1=1$ d. $(-8x)^{0}=-8^{0}x^{0}=1\times1=1$
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