Intermediate Algebra (12th Edition)

Published by Pearson

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 18

Answer

$24s^{7}t^{6}$

Work Step by Step

We are given the expression $(8s^{4}t)(3s^{3}t^{5})$. Before applying the product rule for exponents, we can group like terms. $(8s^{4}t)(3s^{3}t^{5})=(8\times3)(s^{4}\times s^{3})(t\times t^{5})=(24)(s^{4+3})(t^{1+5})=(24)(s^{7})(t^{6})=24s^{7}t^{6}$.

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