## Intermediate Algebra (12th Edition)

$24s^{7}t^{6}$
We are given the expression $(8s^{4}t)(3s^{3}t^{5})$. Before applying the product rule for exponents, we can group like terms. $(8s^{4}t)(3s^{3}t^{5})=(8\times3)(s^{4}\times s^{3})(t\times t^{5})=(24)(s^{4+3})(t^{1+5})=(24)(s^{7})(t^{6})=24s^{7}t^{6}$.