Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises - Page 276: 18

Answer

$24s^{7}t^{6}$

Work Step by Step

We are given the expression $(8s^{4}t)(3s^{3}t^{5})$. Before applying the product rule for exponents, we can group like terms. $(8s^{4}t)(3s^{3}t^{5})=(8\times3)(s^{4}\times s^{3})(t\times t^{5})=(24)(s^{4+3})(t^{1+5})=(24)(s^{7})(t^{6})=24s^{7}t^{6}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.