Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 17

Answer

$18x^{3}y^{8}$

Work Step by Step

We are given the expression $(2x^{2}y^{5})(9xy^{3})$. Before applying the product rule for exponents, we can group like terms. $(2x^{2}y^{5})(9xy^{3})=(2\times9)(x^{2}\times x)(y^{5}\times y^{3})=(18)(x^{2+1})(y^{5+3})=(18)(x^{3})(y^{8})=18x^{3}y^{8}$.
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