Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 15

Answer

$-27w^{8}$

Work Step by Step

We are given the expression $(-3w^{5})(9w^{3})$. Before applying the product rule for exponents, we can group like terms. $(-3w^{5})(9w^{3})=(-3\times9)(w^{5}\times w^{3})$ According to the product rule for exponents, $a^{m}\times a^{n}=a^{m+n}$. Therefore, $(-3\times9)(w^{5}\times w^{3})=(-27)(w^{5+3})=(-27)(w^{8})=-27w^{8}$.
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