Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Review Exercises: 62

Answer

$9t^2-12st+4s^2$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the product of the given expression, $ (3t-2s)^2 ,$ is \begin{array}{l}\require{cancel} (3t)^2+2(3t)(-2s)+(-2s)^2 \\\\= 9t^2-12st+4s^2 .\end{array}
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