Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Review Exercises: 30

Answer

$\frac{3}{2}\times10^{3}$; 1500

Work Step by Step

$\frac{6\times10^{-2}}{4\times10^{-5}}=\frac{6}{4}\times\frac{10^{-2}}{10^{-5}}=\frac{3}{2}\times10^{-2-(-5)}=\frac{3}{2}\times10^{-2+5}=\frac{3}{2}\times10^{3}=1500$
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