Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Review Exercises: 7

Answer

$\frac{1}{30}$

Work Step by Step

$5^{-1}-6^{-1}=\frac{1}{5}-\frac{1}{6}=\frac{1\times6}{5\times6}-\frac{1\times5}{6\times5}=\frac{6}{30}-\frac{5}{30}=\frac{6-5}{30}=\frac{1}{30}$
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