Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Mixed Review Exercises - Page 319: 9

Answer

$\dfrac{1}{16y^{18}}$

Work Step by Step

Using the laws of exponents and the Distributive Property, the given expression, $ (y^6)^{-5}(2y^{-3})^{-4} ,$ simplifies to \begin{array}{l}\require{cancel} y^{6(-5)}(2^{-4}y^{-3(-4)}) \\\\= y^{-30}(2^{-4}y^{12}) \\\\= 2^{-4}y^{-30+12} \\\\= 2^{-4}y^{-18} \\\\= \dfrac{1}{2^{4}y^{18}} \\\\= \dfrac{1}{16y^{18}} .\end{array}
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