Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Mixed Review Exercises - Page 319: 4

Answer

$\dfrac{1}{125}$

Work Step by Step

Using the laws of exponents, the given expression, $ 5^{-3} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{1}{5^3} \\\\= \dfrac{1}{125} .\end{array}
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