## Intermediate Algebra (12th Edition)

First equation: $2x=-3y+1$ $3y=-2x+1$ $y=-\frac{2}{3}x+\frac{1}{3}$ Second equation: $6x=-9y+3$ $9y=-6x+3$ $y=-\frac{6}{9}x+\frac{3}{9}=-\frac{2}{3}x+\frac{1}{3}$ This means that the equations have the same slopes, and the same y-intercepts. Therefore, the equations are dependent, there is infinite solutions.