Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - 3.1 Exercises: 59

Answer

$x=0$ $y=-4$

Work Step by Step

If we add the two equations, we can eliminate the $x$ from the system: $x-\frac{1}{2}y=2$ $-x+\frac{2}{5}y=-\frac{8}{5}$ $-\frac{1}{2}y+\frac{2}{5}y=\frac{2}{5}$ $x=0$ $0.4(0)+0.2y=0$ $y=-4$ $x-\frac{1}{2}(-4)=2$ $x=0$ We have to check, if the solution is right. Substitute $x$ with 0 and $y$ with -4: $0-\frac{1}{2}(-4)=2$ $\checkmark$ $-0+\frac{2}{5}(-4)=-\frac{8}{5}$ $\checkmark$
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