Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - 3.1 Exercises: 48

Answer

$x=1$ $y=1$

Work Step by Step

If we multiply the second equation by $-3$, then we add the two equations, we can eliminate the $y$ from the system: $-2x+3y=1$ $-4\times(-3)x-3y=-3\times(-3)$ $-2x+12x=10$ $x=1$ $-2(1)+3y=1$ $y=1$ We have to check, if the solution is right. Substitute $x$ with 1 and $y$ with 1: $-2(1)+3(1)=1$ $\checkmark$ $-4(1)+1=-3$ $\checkmark$
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