Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - 3.1 Exercises: 43

Answer

$x=0$ $y=0$

Work Step by Step

If we multiply the first equation by $\frac{1}{3}$, the second one by $0.2$, then we add the two equations, we can eliminate the $y$ from the system: $0.4\times \frac{1}{3}x+0.2\times \frac{1}{3}y=0\times \frac{1}{3}$ $\frac{1}{2}\times 0.2x-\frac{1}{3}\times0.2y=0\times 0.2$ $\frac{0.4}{3}x+0.1x=0$ $x=0$ $0.4(0)+0.2y=0$ $y=0$ We have to check, if the solution is right. Substitute $x$ with 0 and $y$ with 0: $0.4(0)+0.2(0)=0$ $\checkmark$ $\frac{1}{2}(0)-\frac{1}{3}(0)=0$ $\checkmark$
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