## Intermediate Algebra (12th Edition)

$m=-\dfrac{3}{2}$
$\bf{\text{Solution Outline:}}$ Use the Slope Formula to find the slope of the line that passes through $(-1,5)$ and $(3,-1).$ $\bf{\text{Solution Details:}}$ With the given points, \begin{array}{l}\require{cancel} y_1= 5 ,\\y_2= -1 ,\\x_1= -1 ,\text{ and }\\ x_2= 3 .\end{array} Using $m=\dfrac{y_1-y_2}{x_1-x_2}$ or the Slope Formula, the slope, $m,$ of the line is \begin{array}{l}\require{cancel} m=\dfrac{y_1-y_2}{x_1-x_2} \\\\ m=\dfrac{5-(-1)}{-1-3} \\\\ m=\dfrac{5+1}{-1-3} \\\\ m=\dfrac{6}{-4} \\\\ m=-\dfrac{3}{2} .\end{array}