Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.6 - Function Notation and Linear Functions - 2.6 Exercises - Page 202: 9

Answer

-11

Work Step by Step

We are given that $g(x)=-x^{2}+4x+1$. In order to evaluate the function at x=-2, we can plug in 0 to the function and evaluate directly. $g(-2)=-x^{2}+4x+1=-(-2)^{2}+4(-2)+1=-(4)+(-8)+1=-4-8+1=-11$
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