Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.6 - Function Notation and Linear Functions - 2.6 Exercises: 28

Answer

$-t^{2}+4t+1$

Work Step by Step

We are given that $g(x)=-x^{2}+4x+1$. In order to evaluate the function at $x=t$, we can plug in $t$ to the function and evaluate directly. $g(t)=-x^{2}+4x+1=-(t)^{2}+4(t)+1=-t^{2}+4t+1$
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