Answer
$-t^{2}+4t+1$
Work Step by Step
We are given that $g(x)=-x^{2}+4x+1$. In order to evaluate the function at $x=t$, we can plug in $t$ to the function and evaluate directly.
$g(t)=-x^{2}+4x+1=-(t)^{2}+4(t)+1=-t^{2}+4t+1$
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