Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.6 - Function Notation and Linear Functions - 2.6 Exercises: 17

Answer

2.75

Work Step by Step

We are given that $g(x)=-x^{2}+4x+1$. In order to evaluate the function at x=.5, we can plug in .5 to the function and evaluate directly. $g(.5)=-x^{2}+4x+1=-(.5)^{2}+4(.5)+1=-(.25)+2+1=-.25+2+1=2.75$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.