## Intermediate Algebra (12th Edition)

$F=86^{\mathrm{o}}$
We got the following equation in Exercise 100: $F=\displaystyle \frac{9}{5}C+32$ We plug in $C=30$ and solve for $F$: $F=\displaystyle \frac{9}{5}(30)+32$ $=54+32$ $=86^{\mathrm{o}}$