Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.3 - Writing Equations of Lines - 2.3 Exercises: 57

Answer

$y=-3$

Work Step by Step

Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the two-point form of linear equations, the equation of the line passing through $\left( \dfrac{1}{2},-3 \right)$ and $\left( -\dfrac{2}{3},-3 \right)$ is \begin{array}{l}\require{cancel} y-(-3)=\dfrac{-3-(-3)}{\frac{1}{2}-\left(-\frac{2}{3}\right)}\left( x-\dfrac{1}{2} \right) \\\\ y+3=\dfrac{0}{\frac{1}{2}+\frac{2}{3}}\left( x-\dfrac{1}{2} \right) \\\\ y+3=0 \\\\ y=-3 .\end{array}
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