Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.3 - Writing Equations of Lines - 2.3 Exercises: 54

Answer

$y=2$

Work Step by Step

Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the two-point form of linear equations, the equation of the line passing through $( -2,2 )$ and $( 4,2 )$ is \begin{array}{l}\require{cancel} y-2=\dfrac{2-2}{-2-4}(x-(-2)) \\\\ y-2=\dfrac{2-2}{-2-4}(x+2) \\\\ y-2=\dfrac{0}{-6}(x+2) \\\\ y-2=0 \\\\ y=2 .\end{array}
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