Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.3 - Writing Equations of Lines - 2.3 Exercises: 53

Answer

$y=5$

Work Step by Step

Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the two-point form of linear equations, the equation of the line passing through $( 2,5 )$ and $( 1,5 )$ is \begin{array}{l}\require{cancel} y-5=\dfrac{5-5}{2-1}(x-2) \\\\ y-5=\dfrac{0}{1}(x-2) \\\\ y-5=0 \\\\ y=5 .\end{array}
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