Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.3 - Writing Equations of Lines - 2.3 Exercises: 52

Answer

$2x-3y=-19$

Work Step by Step

Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the two-point form of linear equations, the equation of the line passing through $( -2,5 )$ and $( -8,1 )$ is \begin{array}{l}\require{cancel} y-5=\dfrac{5-1}{-2-(-8)}(x-(-2)) \\\\ y-5=\dfrac{5-1}{-2+8}(x+2) \\\\ y-5=\dfrac{4}{6}(x+2) \\\\ y-5=\dfrac{2}{3}(x+2) \\\\ 3(y-5)=2(x+2) \\\\ 3y-15=2x+4 \\\\ -2x+3y=4+15 \\\\ -2x+3y=19 \\\\ 2x-3y=-19 .\end{array}
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