Answer
(a) $y=-\frac{3}{4}x+3$
(b) $slope=m=-\frac{3}{4}$
(c) $y-intercept=b=3$; point $(0,3)$
(d) See graph.
Work Step by Step
(a)
A line in slope-intercept form has the equation:
$y=mx+b$ ($m=slope$, $b=y-intercept$)
We put the equation into slope-intercept form:
$3x+4y=12$
$4y=12-3x$
$4y=-3x+12$
$y=-\frac{3}{4}x+3$
(b) We see that $slope=m=-\frac{3}{4}$
(c) We see that $y-intercept=b=3$; point $(0,3)$
(d) See graph.