Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.1 - Linear Equations in Two Variables - 2.1 Exercises - Page 146: 76

Answer

$\displaystyle Midpoint(\frac{11}{20},\frac{-23}{12})$

Work Step by Step

To find the midpoint between points $(x_1,y_1)$ and $(x_2,y_2)$, we use the midpoint formula: $\displaystyle Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$ We use the points $(3/5,-1/3)$ and $(1/2,-7/2)$: $\displaystyle Midpoint=(\frac{3/5+1/2}{2},\frac{-1/3+-7/2}{2})$ $\displaystyle Midpoint=(\frac{6/10+5/10}{2},\frac{-2/6+-21/6}{2})$ $\displaystyle Midpoint=(\frac{11/10}{2},\frac{-23/6}{2})$ $\displaystyle Midpoint=(\frac{11}{20},\frac{-23}{12})$
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