Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.1 - Linear Equations in Two Variables - 2.1 Exercises: 75

Answer

$\displaystyle (\frac{-5}{12},\frac{5}{28})$

Work Step by Step

To find the midpoint between points $(x_1,y_1)$ and $(x_2,y_2)$, we use the midpoint formula: $\displaystyle Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$ We use the points $(-1/3,2/7)$ and $(-1/2,1/14)$: $\displaystyle Midpoint=(\frac{-1/3+-1/2}{2},\frac{2/7+1/14}{2})$ $\displaystyle Midpoint=(\frac{-2/6+-3/6}{2},\frac{4/14+1/14}{2})$ $\displaystyle Midpoint=(\frac{-5/6}{2},\frac{5/14}{2})$ $\displaystyle =(\frac{-5}{12},\frac{5}{28})$
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