Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Review Exercises - Page 211: 52

Answer

-8.52

Work Step by Step

We are given that $f(x)=-2x^{2}+3x-6$. In order to evaluate at $f(2.1)$, we can plug 2.1 into the function and evaluate. $f(2.1)=-2(2.1)^{2}+3(2.1)-6=-2(4.41)+6.3-6=-8.82+6.3-6=-8.52$
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